7x+10=3x^2+30x

Solution for 7x+10=3x^2+30x equation:

7x+10=3x^2+30x

We move all terms to the left:

7x+10-(3x^2+30x)=0

We get rid of parentheses

-3x^2+7x-30x+10=0

We add all the numbers together, and all the variables

-3x^2-23x+10=0

a = -3; b = -23; c = +10;
Δ = b2-4ac
Δ = -232-4·(-3)·10
Δ = 649
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23)-\sqrt{649}}{2*-3}=\frac{23-\sqrt{649}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23)+\sqrt{649}}{2*-3}=\frac{23+\sqrt{649}}{-6}
$